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Energy of H-atom in the ground state is ...

Energy of H-atom in the ground state is `-13.6eV`. Hence energy in the second excited state is

A

`-6.8 eV`

B

`-3.4 eV`

C

`-1.51 eV`

D

`-4.53 eV`

Text Solution

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The correct Answer is:
3
`2^(nd)` excited state will be the `3^(rd)` energy level. `En=13.6/n^(2) eV` or `E=13.6/9=1.51 eV`.
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