The orbital angular momentum for an electron revolving in an orbit is given by `sqrt(l(l + 1))(h)/(2pi)`. What is the momentum of an s-electron?

Options

A. `+1/2. h/(2pi)`
B. Zero
C. `h/(2pi)`
D. `sqrt(2). h/(2pi)`

Answer

2

Explanation

The value of `l` (azimuthal quantum number) for s- electron is equal to zero.
Orbital angular momentum `=sqrt(l(l+1)).(h)/(2pi)`
Substituting the value of `l` for s-electron `=sqrt(0(0+1)).(h)/(2pi)=0`