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The wavelength of the radiation emitted ...

The wavelength of the radiation emitted , when in a hydrogen atom electron falls from infinity to stationary state 1 , would be :
(Rydberg constant = `1.097 xx 10^(7) m^(-1)`)

A

`91 nm`

B

`192 nm`

C

`406`

D

`9.1xx10^(-6) nm`

Text Solution

Verified by Experts

The correct Answer is:
1
`1/lambda=R(1/n_(1)^(2)-1/n_(2)^(2)) 1/lambda=1.097xx10^(7) m^(-1)(1/1^(2)-1/oo^(2)) :. lambda=91xx10^(-9) m=91 m`
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