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The ionization enthalpy of hydrogen atom...

The ionization enthalpy of hydrogen atom is `1.312 xx 10^6 J mol^-1`. The energy required to excite the electron in the atom from `n= 1` to `n = 2` is :

A

`8.51xx10^(5) J mol^(-1)`

B

`6.56xx10^(5) J mol^(-1)`

C

`7.56xx10^(5) J mol^(-1)`

D

`9.84xx10^(5) J mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
4

I.E. `=1.312xx10^(6) J mol^(-1)`
The energy required to excite the electron in the atom from `n_(1)=1` to `n=2`.
`=1.312xx10^(6)[1-1/4]=1.312xx10^(6)xx3/4=9.84xx10^(5) J mol^(-1)`
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