Hydrogen atom:
The electronic ground state of hydrogen atom contains one electron in the first orbit. If sufficient energy is provided, this electron can be promoted to higher energy levels. The electronic energy of a hydrogen-like species (any atom//ions with nuclear charge Z and one electron) can be given as
`E_(n)=-(R_(H)Z^(2))/(n^(2))` where `R_(H)= "Rydberg constant," n= "principal quantum number"`
The ratio of energy of an electron in the ground state `Be^(3-)` ion to that of ground state H atom is:
The kinetic and potential energies of an electron in the H atoms are given as
`K.E. =e^(2)/(4 pi epsilon_(0)2r)` and `P.E.=-1/(4pi epsilon_(0)) e^(2)/r`

Options

A. `16`
B. `4`
C. `1`
D. `8`

Answer

`16`