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Avogadro's Number: 6.022xx10^(23) An a...

Avogadro's Number: `6.022xx10^(23)`
An atom of `..^(238)U` disontegates by a series of `alpha`-decays and `beta`-decays until it becomes `.^(206)Pb`, which is stable.
(i) How many `alpha`-decays and many `beta`-decays does an atom starting as `..^(238)U` undergo before it becomes stable?
(ii) One of the following ten nuclides is formed from a series of disintegrations starting at `..^(238)U`. Which one?
`.^(235)U, .^(234)U, .^(228)Ac, .^(224)Ra, .^(224)Rn, .^(220)Rn, .^(215)Po, .^(212)Po, .^(212)Pb, .^(211)Pb`.

Text Solution

Verified by Experts

The correct Answer is:
(i) `8 alpha's` and `6 beta^(-)'` (only `alpha's` gives `^(206)Os`, to come from Os to Pb requires `6 beta^(-)' s`)
(ii) `^(234)U`, all other answer are incorrect.
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