Home
Class 12
CHEMISTRY
One of naturally occurring radioactive d...

One of naturally occurring radioactive decay series begins with `_(90)^(232)Th` and ends with a stable `_(82)^(208)Pb`.
How many beta `(beta)` decays are there in this series? Show by calculate.

Text Solution

Verified by Experts

The correct Answer is:
`A=232-208=24;" " 24//4=6` alpha perticles
The nuclear charge is therefore reduced by `2xx6=12` units, however, the difference in nuclear charges is only `90-82=8` units. Therefore there must be `12-8=4 beta^(-)` emitted.
Number of beta decays `=4`
Promotional Banner

Similar Questions

Explore conceptually related problems

One of naturally occurring radioactive decay series begins with _(90)^(232)Th and ends with a stable _(82)^(208)Pb . How much energy in MeV is released in the complete chain?

._(90)^(232)Th disintegrates to ._(82)^(208)Pb . How many of beta -particle are evolved?

The end product of the series, starting with ._(90)Th^(232) , is

An artifical radioactive decay series begins with unstable ._94 ^241 Pu . The stable nuclide obtained after eight alpha- decays and five beta^+ - decays is.

._(90)^(234)Th disintegrates to give ._(82)^(206)Pb as the final product. How many alpha and beta particles are emitted in this process?

A radioactive disintegration of ""_(90)Th^(232) yields ""_(82)Pb^(208) in the end . The number of alpha and beta -particle emitted will be

How may alpha- and beta- particles will be emitted when ._(90)Th^(232) changes into ._(82)Pb^(208) ?

In the decay series ._(92)U^(238) to ._(82)Pb^(206) , how many alpha -paritcles and how many beta^(ɵ) -particles are emitted?