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In a process, 701 J of heat is absorbed ...

In a process, `701 J` of heat is absorbed by a system and `394 J` of work is done by the system. What is the change in internal energy for the process?

Text Solution

Verified by Experts

Given `W= -394` (work done by system)
`q=701 J`
Asked `Delta E= ?`
Formula `Delta E = q+w`
Explanation `Delta E=` Change in internal energy
`q="heta"`
`w="work"`
Substitution & calculation
`:. Delta E= 701+(-394)=307 J`.
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