The cell consists of three compartments separated by porous barriers. The first contains a cobalt electrode in 5.00 L of 0.100 M cobalt (II) nitrate, the second contains 5.00 L of 0.100M `AgNO_(3)`. Assuming that the current within the cell is carried equally by the positive and negative ions, tabulate the concentrations of ions of each type in each compartment of the cell after the passage of 0.100 mole electrons.
given `Co^(2+)+2e^(-)toCo" "E^(0)=-0.28V`
`Ag^(+)+e^(-)toAg" "E^(0)=0.80V`
Spontaneous reaction is: `2Ag^(+)+CotoCo^(2+)+2Ag" "1.08V`

Explanation

In the left compartment. Cobalt will be oxidized to cabalt (II) ion. In ht eright compartment, silver ion will be reduced to silver. The passage of 0.100 mol electrons will cause the following quantities of change.
effect of electrode positive ion movement `{:("Compoartment 1","Compartment 2","Copartment 3"),(+0.05000 mol CO^(3+),+0.0250 mol Co^(2+),-0.100molAg^(+)),(-0.0250molCo^(2+),-0.0500molK^(+),+0.0500molK^(+)):}`
Negative ion movement `+0.0500molNO_(3)^(-)`
Changing the numbers of mol to concentrators in 5.0 L compartment and adding or subtracting yields te following results:
Final concentrations (M) `Co^(2+)`