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If resistivity of 0.8M KCl solution is 2...

If resistivity of `0.8M` KCl solution is `2.5xx10^(3)Omega` cm calculate `lamda_(m)` of the solution

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`rho=2.5xx10^(-3)Omegacm`
`K=(10^(3))/(2.5)=4xx10^(2)`
`lamda_(m)=(4xx10^(2)xx1000xx10)/(0.8)=5xx10^(5)Omega^(-1)cm^(2)"mole"^(-1)`
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