Calculate `lamda_(m)^(0)` of oxalic acid, given that
`lamda_(eq)^(0)Na_(2)C_(2)O_(4)=400Omega^(-1)cm^(2)aq^(-1)`
`lamda_(m)^(0)H_(2)SO_(4)=700Omega^(-1)cm^(2)"mole"^(-1)`
`lamda_(eq)^(0)Na_(2)SO_(4)=450Omega^(-1)cm^(2)eq^(-1)`

Explanation

To calculate the molar conductance (λ_m^0) of oxalic acid (H2C2O4), we will use the given data and the relationships between molar conductance and equivalent conductance. Here’s a step-by-step solution:

### Step 1: Understand the Relationships
The molar conductance (λ_m^0) of oxalic acid can be expressed in terms of the conductance of its ions:
\[ \lambda_m^0(H_2C_2O_4) = 2 \cdot \lambda_m^0(H^+) + \lambda_m^0(C_2O_4^{2-}) \]
This equation indicates that the molar conductance of oxalic acid is the sum of the conductances of the hydrogen ions and the oxalate ions.
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