to calculate `K_(W)` of water
`H_(2)O(l)+H_(2)O_(l)toH_(2)O^(+)(aq)+OH^(-)(aq)`
`lamda_(m)=lamda_(M.H_(2)O)^(0)=lamda_(M)^(0)H^(+)+lamda_(M)^(0)OH^(-)`
`=(Kxx1000)/("molarity")-` concentration of water molecules `100%` dissociated ask
Molarity `=[H^(+)]=[OH^(-)]=(Kxx100)/(lamda_(M)^(infty))`
`K_(W)=[H^(+)][OH^(-)]=[(Kxx1000)/(lamda_(M)^(0))]K_(a)` or `K_(b)=([H^(+)][OH^(-)])/(H_(2)O)`