How long a current of 3 ampere has to be passed through a soulution of silver nitrate to coat a metal. Surface of `80cm^(2)` with a 0.005 mm thick layer? Density of Ag is `10.5gcm^(-3)`. At wt. `Ag=108.0u`

Explanation

To solve the problem step by step, we will follow the outlined procedure to find out how long a current of 3 amperes must be passed through a solution of silver nitrate to coat a metal surface of 80 cm² with a thickness of 0.005 mm.

### Step 1: Convert the thickness from mm to cm
The thickness of the silver layer is given as 0.005 mm. We need to convert this to centimeters for consistency with the area measurement.

\[ \text{Thickness in cm} = 0.005 \, \text{mm} \times \frac{1 \, \text{cm}}{10 \, \text{mm}} = 0.0005 \, \text{cm} \]
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