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The standard oxidation potential for the...

The standard oxidation potential for the half-cell
`NO_(2)^(-)(g)+H_(2)OtoNO_(3)^(-)(aq)+2H^(+)(aq)+2e` is `-0.78V`.
Calculate the reduction in 9 molar `H^(+)` assuming all other species at unit concentration. What will be the reduction potential in neutral medium?

Text Solution

Verified by Experts

The correct Answer is:
`0.836"volt", 1.1937"volt"`

`E_("oxidation")=-0.78-(0.0591)/(2)log9^(2)=-0.78-(0.0591)/(2)xx2xxlog9=-0.835"volt"`
`E_("reduction")=-E_("oxidation")=0.836"volt"`
In neutral medium
`E_("Oxidation")=-0.78-(0.0591)/(2)log(10^(-7))^(2)=-1.1937"volt"`
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