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Calculate the dissociation canstant of w...

Calculate the dissociation canstant of water at `25^(@)C` from te followig data specific conductance of `H_(2)O=5.8xx10^(-8)mhocm^(-1),lamda_(H^(+))^(infty)=350.0` and `lamda_(OH)^(infty)=198.0mhocm^(2)mol^(-1)`

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The correct Answer is:
`2xx10^(-16)"mole"//"litre"`
`K=5.8xx10^(-8)Scm^(-1)`,`^^_(H^(+))^(@)=350Scm^(2)`,^^_(OH^(-))^(@)=198Scm^(2)`
`^^_(H_(2)O)=(1000xx5.8xx10^(-8))/(55.5),alpha=(^^H_(2)O)/(^^H_(2)O)=((1000xx5.8xx10^(-8)))/(55.5xx(350+198))=0.1907xx10^(-8)=1.907xx10^(-9)`
`K_(a)=Calpha^(2)=55.55xx(1.907)^(2)xx10^(-18)=2.02xx10^(-16)`
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