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Pt | H(2) | pH = 1 || pH = 2 | (H(2))Pt ...

`Pt | H_(2) | pH = 1 || pH = 2 | (H_(2))Pt`
1 atm 1 atm
The cell reaction for the given cell is:

A

Spontaneous

B

non-spontaneous

C

Equilibrium

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`H_(2)to2H_((10^(-2)M))^(+)+2e^(-)`
`2H_((10^(-3)M))^(+)+2e^(-)toH_(2)`
`2H_((10^(-3)M))^(+)to2H_((10^(-2)M))^(+)`
`E=0-(0.0591)/(2)log((10^(-1))/(10^(-2)))^(2)`
`Etove` (non spontaneous).
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