The solubiltiy product of silver iodide is `8.3 xx 10^(-17)` and the standard potential (reduction) of `Ag,Ag^(+)` electrode is `+0.800` volts at `25^(@)C`. The standard potential of `Ag,AgI//I^(-)` electrode (reduction) from these data is

Options

A. `-0.30V`
B. `+0.15V`
C. `+0.10V`
D. `-0.15V`

Answer

D

Explanation

`E_(I^(-)//Agl//Ag)=0.8-(0.0591)/(1)log((1)/(K_(SP))`
`=0.8+0.0591xxlog8.3xx10^(-17)=-0.15"volt"`
or `E_(Ag//AgI//I^(-))^(@)=E_(Ag//Ag^(+)+(RT)/(F))^(@).ln(1)/(k_(SP))`
`=0.8-(8.31xx298xx2.303)/(96500)logk_(sp)=-0.8-0.0591.log8.3xx10^(17)=0.8+0.095=0.15V`.