The potential of the Daniel cell, `Zn |(ZnSO_(4))||(CuSO_(4)|Cu` was reported by Buckbee, Surdzial and Metz as `E^(@) = 1.1028 - 0.641 xx 10^(-3)T` + `0.72 xx 10^(-5)T^(2)`, where T is the temperature in degree celcius, Calcualte `DeltaS^(@0` for the cell reaction at `25^(@)C`.

Options

A. `-45.32EU`
B. `-34.52EU`
C. `-25.43EU`
D. `-54.23EU`

Answer

D

Explanation

`E^(@)=1.1028-0.641xx10^(-3)T+0.72xx10^(-5)T^(2)`
`((dE^(@))/(dT))_(2S)=-0.641xx10^(-3)+2xx0.72xx10^(-5)T=(-0.641+0.36)xx10^(-3)=-0.281xx10^(-3)`
`triangleS^(@)=nF(dE)/(dT)=2xx96500xx(-281xx10^(3))=-54.23EU`