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DeltaG = DeltaH - TDeltaS and DeltaG + T...

`DeltaG = DeltaH - TDeltaS` and `DeltaG + T[(d(DeltaG))/(dT)]_(p)` then `((dE_(cell)/(dT))` is:

A

`(trangleS)/(nF)`

B

`(nE)/(triangleS)`

C

`-nFE^(cell)`

D

`+nEF_(cell)`

Text Solution

Verified by Experts

The correct Answer is:
A
`triangleS-{(d)/(dT)(triangleG)}_(P)=+nF((dE)/(dT))_(p)`
`((dE)/(dT))_(p)=(triangleS)/(nF)`
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