One g equivalent of Na metal is formed from electrolyis of fused NaCl. No of "mole" of Al from the fused `Na_(3)AlF_(6)` with the same current passed is:

Options

A. 1
B. 3
C. `1//3`
D. `2`

Answer

C

Explanation

`underset(1" mole")(Na^(+))+underset(1" faraday")(e^(-)to)Na(s)`
`AP^(+)+underset(1" faraday")(3e^(-)to)Al(s)`
No. of mole of `Al=(1)/(3)` mole