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If 0.224 L of H(2) gas is formed at the ...

If 0.224 L of `H_(2)` gas is formed at the cathode, the volume of `O_(2)` gas formed at the anode under identical conditions, is:

A

0.224 L

B

0.448 L

C

0.112 L

D

1.12L

Text Solution

Verified by Experts

The correct Answer is:
C
Equivalent of `H_(2)=` equivalence of `O_(2)`
`(0.224)/(22.4)xx2=("volume of "O_(2))/(22.4)xx4`
`0.112` litre `="volume of " O_(2)`
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