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Estimate the cell potential of a Daniel ...

Estimate the cell potential of a Daniel cell having `1.0Zn^(++)` and originally having `1.0M Cu^(++)` after sufficient `NH_(3)` has been added to the cathode compartment to make `NH_(3)` concentration `2.0M`. Given `K_(f)` for `[Cu(NH_(4))_(4)]^(2+) = 1xx 10^(12), E^(@)` for the reaction, `Zn +Cu^(2+) rarr Zn^(2+) +Cu` is `1.1V`

Text Solution

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The correct Answer is:
`E^(@)=0.71V`
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