what is the emf at `25^(@)C` for the cell,
`Ag|{:(AgBr(s)" " Br^(-)), (" "alpha = 0.34):}||{:(Fe^(3+) " " Fe^(2+)), (alpha = 0.1 " " alpha = 0.02):}|Pt`
The standard reduction potentials for the half-reactions `AgBr + e^(-) rightarrow Ag + Br^(-) and Fe^(3+) + e^(-) rightarrow Fe^(2+)` are +0.0713V and +0.770V respectively.

Options

A. 0.474 volt
B. 0.529 volt
C. 0.356 volt
D. 0.713 volt

Answer

D

Explanation

`E_(cell)=(0.77-0.0713)-(0.059)/(1)log((0.02)/(0.1xx0.34))=0.713"volt"`