The electrode potential of electrode
`M(s) rightarrow M^(n+) (aq) (2M) + ne^(-)` at 298 K is E_(1). When temperature is doubled and concentration is made half, then the electrode potential becomes `E_(2)`. Which of the following represents the correct relationship between `E_(1)` and `E_(2)`?

Options

A. `E_(1)gtE_(2)`
B. `E_(1)ltE_(2)`
C. `E_(1)=E_(2)`
D. Can't be predicted.

Answer

B

Explanation

`E_(1)=E^(@)=-(RT)/(nF)ln2`
`E_(2)=E^(@)-(Rxx2T)/(nF)ln1=E^(@)`
`thereforeE_(2)gtE_(1)`