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The reduction potential of a half-cell c...

The reduction potential of a half-cell consisting of a Pt electrode immersed in `1.5 M Fe^(2+)` and ` 0.015 M Fe^(3+)` solutin at `25^@ C` is `(E_(Fe^(3+)//Fe^(2+))^@ = 0.770 V)` is .

A

0.652 V

B

0.88 V

C

0.710 V

D

0.850 V

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(cell)=0.77-(0.059)/(1)log((1.5)/(0.015))=0.652`V
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