If the pressure of hydrogen gas is increased from 1 atm. To 100 atm, keeping the hydrogen ion concentration constant at 1 M, the reduction potential of the hydrogen half cell is at `25^(@)C` will be

Options

A. 0.059 V
B. `-0.059V`
C. `0.295V`
D. `0.118V`

Answer

B

Explanation

`E_(H_(2)//H^(+))=-(0.0591)/(1)log_(10)((sqrt(pH_(2)))/([H^(+)]))`,`H^(+)+e^(-)to(1)/(2)H_(2)`