The `E^(@)` in the given figure is

Options

A. `0.5`
B. `0.6`
C. `0.7`
D. `0.8`

Answer

B

Explanation

`ClO_(3)^(-)+2H_(2)O+4etoClO^(-)+4OH^(-):triangleG_(1)^(@)`
`ClO^(-)+H_(2)O+eto(1)/(2)+2OH^(-),triangleG_(2)^(@)`
`underline((1)/(2)Cl_(2)+etoCl^(-),triangleG_(3)^(@))`
`underline(ClO_(3)^(-)+3H_(2)O+3etoCl^(-)+6OH^(-),triangleG^(@))`
`thereforetriangleG^(@)=triangleG_(1)^(@)+triangleG_(2)^(@)+triangleG_(3)^(@)`
`-6FE^(@)=-4Fxx0.54-1Fxx0.45-1Fxx1.07`
`thereforeE^(@)=+(3.68)/(6)=+0.61V`