A current is passed through 2 voltmeters connected in series. The first voltmeter contians `XSO_4)(aq)` and second has `Y_(2)SO_(4)`(aq). The relative atomic masses of X and Y are in the ratio `2:1`. The ratio of the mass of X liberated to the mass of Y liberated is:

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. none of above

Answer

A

Explanation

`(m_(X))/(m_(Y))=((A_(X))/(2)xxQ)/((A_(Y))/(1)xxQ)implies(m_(X))/(m_(Y))=1becauseA_(X)=2A_(Y)`