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A certain current liberated 0.504 g of h...

A certain current liberated 0.504 g of hydrogen in 2 hours. How many gram of copper can be liberated by the same current flowing for the same time in `CuSO_(4)` solution ?

A

31.8 g

B

16.0 g

C

12.7 g

D

63.5 g

Text Solution

Verified by Experts

The correct Answer is:
C
`(W_(1))/(E_(1))=(W_(2))/(E_(2))`
`(W_(Cu))/((63.5)/(2))=(0.504)/((2)/(2))`
`W_(Cu)=0.504xx63.5=31.8gm`.
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