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Time required to deposit one milli"mole"...

Time required to deposit one milli"mole" of aluminium metal by the passage of 9.65 amp through aqueous solution of aluminium ion is:

A

30 s

B

10 s

C

30,000s

D

10,000s

Text Solution

Verified by Experts

The correct Answer is:
B
`(9xx10^(-3))/(27)xx3=(9.65xxt)/(96500),t=(30)/(27)xx9=10sec`
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