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The pK(sp) of AgI is 16.07 if the E^(@) ...

The `pK_(sp)` of `AgI` is `16.07` if the `E^(@)` value for `Ag^(+)//Ag` is `0.7991V`, find the `E^(@)` for the half cell reaction `AgI(s) +e^(-) rarr Ag+I^(-)`

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The correct Answer is:
`E^(@)=-0.149V`.
`E^(@)=0.7991+(0.0591)/(1)logK_(SP)=0.0791-0.0591xxpK_(SP)=-0.149"volt"`
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