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Calculate the e.m.f. of the cell Pt|H(...

Calculate the e.m.f. of the cell
`Pt|H_(2)(1.0atm)|CH_(3)COOH (0.1M)||NH_(3)(aq,0.01M)|H_(2)(1.0atm)|Pt`
`K_(a) (CH_(3)COOH) =1.8 xx 10^(-5), K_(b),(NH_(3)) = 1.8 xx 10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
`-0.46V`
`E=0-(0.0591)/(2)log((0.1xx1.8xx10^(-5))/([H^(+)]_(NH_(3))^(2)))`
`([OH^(-)]^(2))/(0.01)=1.8xx10^(-5)implies[H^(+)]^(2)=((10^(-14))^(2))/(1.8xx10^(-7))impliesE=-0.46"volt"`
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