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After electrolytes of NaCl solution with...

After electrolytes of NaCl solution with inert electrodes for a certain period of time 600 mL of the solution was left which was found to be 1N in NaOH. During the same time, 31.75 g of Cu deposited in the copper voltmeter in seris with the electrolytic cell. Calcualte the percentage yield of NaOH obtained.

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The correct Answer is:
`60%`
Equivalent of Cu deposited `=(31.75xx2)/(63.5)=1`
equivalent of NaOH formed `=0.6xx0.6`
`%` yield of `NaOH=60%`
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