Specific conductance of pure water at `25^(@)C` is `0.58 xx 10^(-7)` mho `cm^(-1)`. Calculate ionic product of wter `(K_(w))` if ionic conductances of `H^(+)` and `OH^(-)`ions at infinite are `350` and `198` mho `cm^(2)` respectively at `25^(@)C`

Answer

`1xx10^(-14)("mole"//"litre"^(2))`

Explanation

`(^^)_(m)^(infty)=350+198=(0.58xx10^(-7)xx1000)/(M)impliesM=1.06xx10^(-7)` and `K_(w)=M^(2)=1.12xx10^(-14)`