What is an adsorption isotherm ?

Answer

It represents the varition of the mass of the gas adsorbed per gram of the adsorbent with pressure at constant temperature.

Explanation

(a) `2Br^(-)(aq) +H_(2)O_(2)(aq)+2H^(+)(aq) rarrBr_(2)(l)+2H_(2)O(l)`
rate=`k [H_(2)O_(2)][H^(+)][Br^(-)]=(-1)/2(d[Br^(-)])/(dt)=(-d[H_(2)O_(2)])/(dt)`
`R_(1)=k [H_(2)O_(2)][H^(+)][Br^(-)]=3R_(1)`
`-(d[Br^(-)])/(dt)=3R_(1)=k^(1)[H_(2)O_(2)][H^(+)][Br^(-)]`
(b) `(-1)/2(d[Br^(-)])/(dt)=(-d[H_(2)O_(2)])/(dt)=(-1)/2(d[H^(+)])/(dt)=(+d[Br_(2)])/(dt)=(+1)/2(d[H_(2)O])/(dt)`
`(-1)/2(d[Br^(-)])/(dt)=(-d[H_(2)O_(2)])/(dt)=(d[Br_(2)])/(dt)`
`1/2[(-d[Br^(-)])/(dt)]=(-d[H_(2)O_(2)])/(dt)=+(d[Br_(2)])/(dt)`
`1/2[7.2xx10^(-3)]=(-d[H_(2)O_(2)])/(dt)=+(d[Br_(2)])/(dt)`
3.6xx10^(-3)=(-d[H_(2)O_(2)])/(dt)=+(d[Br_(2)])/(dt)`
(c) No effect
(d) r_(1)=k [H_(2)O_(2)][H^(+)][Br^(-)]=(-d[Br^(-)]_(1))/(dt)`
`r_(2)=k ([H_(2)O_(2)])/(2) ([H^(+)])/2 ([Br^(-)])/2=(-d[Br^(-)]_(2))/(dt)`
`r_(2)=1/8[k(H_(2)O_(2))][H^(+)][Br^(-)]=(-d[Br^(-)]_(2))/(dt)`
`=1/8 r_(1)=(-d[Br^(-)]_(2))/(dt)`