The initail and final position vectors for a particle are respectively , `( - 3.0 m)hati + (2.0 m) hat j + (8.0 m ) hatk` and `(9.0 m)hati + (2.0 m )hatj + (- 8.0 m )hat k` . The displacement of the particle is

The initial and final position vector for a particle are(-3m) hati+(2m)hatj+(8m)hatk and (9m)hati+(2m) hatj+(-8m)hatk respectively ,find the displacement of the particle.

the initial and final and posdition vector for a particle are(-3) hati+(2m)hatj+(8m)hatk and (9m)hati+(2m) hatj+(-8m)hatk respectively ,find the displacement of the particle.

The position vector for an electron is vecr=(6.0m)hati-(4.0m)hatj+(3.0m)hatk . (a) Find the magnitude of vecr .

The set of values of 'm' for which the vectors vec(a) = mhati + (m + 1)hatj +(m + 8)hatk vec(b) = (m + 3)hati + (m+4)hatj + (m +5) hatk and vec(c) = (m + 6)hati + (m + 7)hatj + (m + 8) hatk are non - coplanar is

Consider two vectors veca = (5.0) hati - (4.0) hatj + (2.0) hatk and vecb = (-2.0m) hati + ( 2.0)m hatj + (5. 0m) hatk, where m is a scalar. Find (a) veca + vecb , (b) veca - vecb , and (c ) a thirs vector vecc such that veca - vecb + vec c =0.

The vector veca = hati + hatj + (m + 1) hatk , vecb = hati + hatj + m hatk.vecc = hati - hatj + m hatk are coplanar for :

If a force of (8.0 hati+2.0 hatj+3 hatk)N displaces a body through a distance of (6.0 hati-3 .0 hatj -9 hatk) m . The work done will be

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.