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Charges Q1 and Q2 are at points A and B ...

Charges `Q_1 and Q_2` are at points A and B of a right angle triangle OAB (see figures) . The resultant electric field at point O is perpendicular to the phypotenuse, then `Q_1//Q_2` is proportional to :

A

`(x_1^3)/(x_2^3)`

B

`(x_2)/(x_1)`

C

`(x_1)/(x_2)`

D

`(x_2^2)/(x_1^2)`

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