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You are given that mass of ""(3)^7Li = 7...

You are given that mass of `""_(3)^7Li = 7.0160 u, `
Mass of `""_(2)^(4)He = 4.0026 u`
and Mass of `""_(1)^(1)H = 1.0079 u`
When 20 g of `""_(3)^(7)Li` is converted into `""_(2)^(4)He` by proton capture , the energy liberated , (in kWh) , is :
[ Mass of nucleon = 1` GeV//c^2)`]

A

`4.5 xx 10^5`

B

`8xx10^6`

C

`6.82 xx 10^5`

D

`1.33xx10^6`

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