Suppose that intensity of a laser is `((315)/(pi)) W//m^2` . The rms electric field, in units of V/m associated with this source is close to the nearest with this source is close to the nearest integer is _______ .
`(in_0 = 8.86 xx 10^(-12) C^2 Nm^(-2) , c= 3 xx 10^8 ms^(-1))`

The intensity of light from a source is 500//pi W//m^(2) . Find the amplitude of electric field in the wave-

The energy density of air medium is 44.25 xx 10^(-8) J//m^(3) . The intensity of the electric field in the medium is

The energy density of air medium is 44.25xx10^(-8)J//m^(3) . The intensity of the electric field in the medium is

A laser beam has intensity 2.5xx10^(14)W/(m^(2)) . Find the amptitude of electric field (in V/m) in the beam.

A radiation is emitted by 1000 W bulb and it generates an electric field and magnetic field at P, placed at a distance of 2 m. The efficiency of the bulb is 1.25%. The value of peak electric field at Pis "x"xx10^(-1)V//m . Value of x is_ (Rounded-off to the nearest integer) [Take epsi_0=8.85xx10^(-12)C^2N^(-1)m^(-2),c=3xx10^8ms^(-1)

The energy density in an electric field of intensity 200 "volt"//m , if K=4 and epsi_(0)=8.85 xx 10^(-12) C^(2)//Nm^(2) is

What is the energy stored per unit volume in vacuum, where the intensity of electric field is 10^(3)V//m ? (epsi_(0)=8.85xx10^(-12)c^(2)//N-m^(2))

The mean intensity of radiation on the surface of the Sun is about 10^(s)W//m^2 . The rms value of the corresponding magnetic field is closed to :

A laser beam has intensity 2.5 xx (10^14)W (m^-2). Find the amplitudes of electric and magnetic fields in the beam.

A cube of marble having each side 1 cm is kept in an electric field of intensity 300 V/m. Determine the energy contained in the cube of dielectric constant 8. [Given : epsilon_(0) =8.85 xx 10^(-12) C^(2)//Nm^(2) ]