A rod is heated from `0^@` to `10^@` its length is changed by `0.02%` by what `%` mass density is changed?

Options

A. `0.06`
B. `0.008`
C. `2.3`
D. `0.8`

Answer

A

Explanation

`Deltal = l prop Delta t `
`alpha = (Deltal)/(lDeltal) = (0.02)/(100 xx 10) = 2xx 10^(-5)`
` v =3 alpha = 6xx 10^(-5)`
Now , `(Deltav)/v = 100 = gamma . Deltat 100 = 6 xx 10^(-5) xx 10 xx100`
` 6xx 10^(-2) = 0.06`