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A 10 muF capacitor is charged to a poten...

A `10 muF` capacitor is charged to a potential difference of `50 V` and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes `20` volt. The capacitance of second capacitor is

A

`15 mu `F

B

`20 muF`

C

`10 mu` F

D

`30 mu ` F

Text Solution

Verified by Experts

The correct Answer is:
A

`C_(1) = 10 muF`
`v_(t) = 20v `
` 500/(C_(1) +C_(2)) = 20 `
`500 /(10+C_(2)) = 20 `
` 10 + C_(2) = 500/20 = 25`
` C_(2) = 15 muF `
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