A ray incident at an angle of incidence `60^(@)` enters a glass sphere of `mu=sqrt(3)` and it is reflected and refracted at the farther surface of the sphere. The angle between reflacted and refracted rays at this surface is

Explanation

At `S_(1)`
` 1 xx sin 60^(@) = sqrt(3) ` sin r
` r = 30^(@)`
` :. r_(1) = 30^(@)` {from geometry}
As `S_(2) sqrt(3) "sim"r_(1)= 1 ` sin e
` e = 60^(@)`
Now , `r_(1) + theta + e = 180^(@)`
` theta = 90^(@)`