A wire of density `9 xx 10^(3) kg//m^(3)` is stretched between two clamps 1 m apart and is subjected to an extension of `4.9 xx 10^(-4) m`. The lowest frequency of transverse vibration in the wire is `(Y = 9 xx 10^(10) N//m^(2))`

Answer

35

Explanation

` f = 1/(2l) sqrt(T/mu) = 1/(2l) sqrt(T/(rhoA)) =1/(2l) sqrt((YDeltal)/(rhol))`
` f = 1/(2xx1 ) sqrt((9xx10^(10)xx4.9 xx10^(-4))/(9000xx1))`
` = 1/2 sqrt(49 xx 100) = 35 ` Hz