The surface of a metal is illuminated alternately with photons of energies `E_(1) = 4 eV ` and `E_(2) = 2.5 eV` respectively. The ratio of maximum speeds of the photoelectrons emitted in the two cases is 2. The work function of the metal in (eV) is ________.

A metal surface is illuminated by the protons of energy 5 eV and 2.5 eV respectively . The ratio of their wavelength is

A photonsensitive metallic surface is illuminated alternately with light of wavelength 3100 Å and 6200 Å . It is observed that maximum speeds of the photoelectrons in two cases are in ratio 2 : 1 . The work function of the metal is (hc = 12400 e VÅ)

A metallic surface is illuminated alternatively with light of wavelenghts 3000 Å and 6000 Å . It is observed that the maximum speeds of the photoelectrons under these illuminations are in the ratio 3 : 1 . Calculate the work function of the metal and the maximum speed of the photoelectrons in two cases.

Surface of certain metal is first illuminated with light of wavelength lambda_(1)=350 nm and then, by light of wavelength lambda_(2)=540 nm. It is found that the maximum speed of the photo electrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to : (Energy of photon =(1240)/(lambda("in nm"))Ev

Two photons of energies twice and thrice the work function of a metal are incident on the metal surface. Then the ratio of maximum velocity of the photoelectrons emitted in the two cases respectively, is

Two differenct photons of energies, 1 eV and 2.5 eV, fall on two identical metal plates having work function 0.5 eV, Then the ratio of maximum KE of the electrons emitted from the two surface is -

When photons of energy 5 eV fall on a photosensitive surface, the maximum K.E. of the photoelectrons emitted from the surface is 2.5 eV. What is the stopping potential ?

The energy of emitted photoelectrons from a metal is 0.9ev , The work function of the metal is 2.2eV . Then the energy of the incident photon is

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?