`[x] > -0.5` [.] = G. I. F then

Let f(x)=x^(5)[1/(x^(3))],x!=0 & f(0)=0 (where [.] represent G.I.F.), Then lim_(xto0)f(x)

Let f ( x) = int _ 0 ^ x g (t) dt , where g is a non - zero even function . If f(x + 5 ) = g (x) , then int _ 0 ^ x f (t ) dt equals :

Let f ( x) = int _ 0 ^ x g (t) dt , where g is a non - zero even function . If f(x + 5 ) = g (x) , then int _ 0 ^ x f (t ) dt equals :

Let f(x)=2x +5 and g(x)=x^2+xdot Describe i. f+g ii. f-g iii. fg iv. f//g . Find the domain in each case.

Let f(x)=2x +5 and g(x)=x^2+xdot Describe i. f+g ii. f-g iii. fg iv. f//g . Find the domain in each case.

Let f (x) = [x] and g (x ) =|x| , AA x in R then value of gof (( - 5 ) /(3)) + fog (( - 5)/(3)) is equal to: ( where f _ 0 g (x) = f (g (x))) .

If f(x) = 3^(x) " and" g(x) = 4^(x) , " then" (f'(0) - g'(0))/(1 +f'(0) g'(0)) is

Let f(x) = e^(x)g(x) , g(0)=2 and g (0)=1 , then find f'(0) .