The pressure (`1xx 10^5` newton//`m^2`) fo the air filled in a vessel is decreased adiabatically so much as to increase its volume three times. Calculate the pressure of air. `gamma` for air = 1.4, `log_10 3= 0.4771, log_10 2.148 = 0.33206`.

Explanation

To solve the problem of finding the pressure of air after adiabatically increasing its volume three times, we can follow these steps:

### Step 1: Understand the Adiabatic Process
In an adiabatic process, the relationship between pressure and volume is given by the equation:
\[ P_1 V_1^\gamma = P_2 V_2^\gamma \]
where:
- \( P_1 \) = initial pressure
- \( V_1 \) = initial volume
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