A carnot engine takes in 3000 kcal of heat from a reservoir at `627^@C` and gives a part of it to a sink at `27^@C`. The work done by the engine is

Options

A. `4.2 xx 10^6 J`
B. `8.4 xx 10^6 J`
C. `16.8 xx 10^6J`
D. Zero

Explanation

To solve the problem of finding the work done by the Carnot engine, we will follow these steps:

### Step 1: Identify the given values
- Heat absorbed from the hot reservoir (Q1) = 3000 kcal
- Temperature of the hot reservoir (T1) = 627°C
- Temperature of the cold reservoir (T2) = 27°C

### Step 2: Convert temperatures to Kelvin
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