A : Coefficient of performanceof a refreigerator is always greater than 1.
R : Efficiencyof heat engine is greater than 1.

Options

A. If both Assertion & Reason are true and the reason is the correct explantion of the assertion, then mark(1)
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2).
C. If Assertion is true statement but Reason is false, then mark (3).
D. If both Assertion and Reason are false statements, then mark (4)

Answer

To analyze the statements given in the question, we need to evaluate both the Coefficient of Performance (COP) of a refrigerator and the efficiency of a heat engine.

### Step-by-step Solution:

1. **Understanding the Coefficient of Performance (COP) of a Refrigerator:**
- The COP of a refrigerator is defined as the ratio of the heat removed from the cold reservoir (Q) to the work input (W) required to remove that heat.
- Mathematically, it is expressed as:
\[ \text{COP} = \frac{Q}{W} \]
- Since the work done (W) is always a positive quantity, and the heat extracted (Q) is also positive, the COP will always be greater than 1 for a refrigerator operating in a cycle.

2. **Understanding the Efficiency of a Heat Engine:**
- The efficiency (η) of a heat engine is defined as the ratio of the work output (W) to the heat input (Q).
- Mathematically, it is expressed as:
\[ \eta = \frac{W}{Q} \]
- According to the second law of thermodynamics, not all the heat energy (Q) can be converted into work (W); some energy is always lost as waste heat. Therefore, the efficiency of a heat engine is always less than 1.

3. **Conclusion:**
- The statement A is correct: The coefficient of performance of a refrigerator is always greater than 1.
- The statement R is incorrect: The efficiency of a heat engine is always less than 1.

### Final Answer:
- A is true, R is false.