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A wave travelling in positive X-directio...

A wave travelling in positive X-direction with `A=0.2m` has a velocity of `360m//sec` . If `lambda=60m` , then correct expression for the wave is

A

`y=0.2 sin [2 pi ( 6t+(x)/(60))]`

B

`y=0.2 sin [ pi ( 6t+(x)/(60))]`

C

`y=0.2 sin [2 pi ( 6t-(x)/(60))]`

D

`y=0.2 sin [ pi ( 6t-(x)/(60))]`

Text Solution

Verified by Experts

The correct Answer is:
C
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A wave represented by the given equation Y = A sin (10 pi x + 15 pi t + (pi)/(3)) , where x is in meter and t is in second. The expression represents (1) A wave travelling in the negative X direction with a velocity of 1.5 m/sec (2) A wave travelling in the negative X direction with a wavelength of 0.2 m (3) A wave travelling in the positive X direction with a velocity of 1.5 m/sec. (4) A wave travelling in the positive X direction with a wavelength of 0.2 m

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Knowledge Check

  • A wave travelling in positive X-direction with A=0.2m has a velocity of 360 m//sec if lamda=60m , then correct exression for the wave is

    A
    `y=0.2sin[2pi(6t+(x)/(60))]`
    B
    `y=0.2sin[pi(6t+(x)/(60))]`
    C
    `y=0.2sin[2pi(6t-(x)/(60))]`
    D
    `y=0.2sin[pi(6t-(x)/(60))]`
  • A wave travelling in positive X-direction with A=0.2m has a velocity of 36 m//sec if lambda=60m , then correct exression for the wave is

    A
    `y=0.2sin[2pi(6t+(x)/(60))]`
    B
    `y=0.2sin[pi(6t+(x)/(60))]`
    C
    `y=0.2sin[2pi(6t-(x)/(60))]`
    D
    `y=0.2sin[pi(6t-(x)/(60))]`
  • A wave travelling in positive x-direction with a=0.2 m/s. Velocity = 360 m/s. and lambda = 60 m, then correct expression for the wave is

    A
    `y = 0.2 sin [2pi (6t + x/60)]`
    B
    `y =0.2 sin[pi(6t+x/60)]`
    C
    `y=0.2 sin[2pi(6t-x/60)]`
    D
    `y=0.2sin[pi(6t -x/60)]`
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