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In a neon discharge tube 2.9 xx 10^(18) ...

In a neon discharge tube `2.9 xx 10^(18) Ne^(+)` ions move to the right each second while `1.2 xx 10^(18)` eletrons move to the left per second. Electron charge is `1.6 xx 10^(-9) C`. The current in the discharge tube

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Here since positive negative charges are moving is opposite dierection their equaivalent current is in the same direction i.e., in the direction in which the positive ions are moving . So the total currect will be the sum of the currents due to individual positive and negative charges.
Hence net current ` = ((n_(p) + n_(e))e)/(t) = ((2.9 xx 10^(18) + 1.2 xx 10^(18)) xx 1.6 x 10^(18))/(1s) = 0.66 A` to right i.e, the direction in which the positive charge is moving .
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